Question

(3/7×2 1/3+4 1/6×2/5–1/4)×(1 5/29) ​

Answer 1

Răspuns:

[3/7*(2*3+1)/3+(4*6+1)/6*2/5-1/4)*(1*29+5)/29=

(3/7*7/3+25/6*2/5-1/4)*34/29=

(¹²⁾1+⁴⁾5/3-³⁾1/4)*34/29=

(12+20-3)/12*34/29=

29/12*34/29=

(34/12)⁽²=17/6=

2 intregi 5/6