Question

3^90-4*9^44+2^208÷(2*4^103)-5*(9^22)^2=​

Answer 1

Răspuns:

4

Explicație pas cu pas:

3^90-2²×3^88+2^208: 2×2^206-5×3^88=3^88×(9-4-5)+2²=0+4=4

Answer 2

3⁹⁰-4×9⁴⁴+2²⁰⁸÷(2×4¹⁰³)-5×(9²²)²=

3⁹⁰-4×9⁴⁴+2²⁰⁸÷(2×(2²)¹⁰³)-5×9⁴⁴=

3⁹⁰-4×9⁴⁴+2²⁰⁸÷(2×2²⁰⁶)-5×9⁴⁴=

3⁹⁰-4×9⁴⁴+2²⁰⁸÷2²⁰⁷-5×9⁴⁴=

3⁹⁰-4×9⁴⁴+2-5×9⁴⁴=

3⁹⁰+2+9⁴⁴(-4-5)=

3⁹⁰+2+(-9)×9⁴⁴=

3⁹⁰+2-9⁴⁵=

2+3⁹⁰-(3²)⁴⁵=

2+3⁹⁰-3⁹⁰=

=2