Question

3^90-4x9^44+2^208:(2x4^103)-5x(9^22)^2

Answer 1

Răspuns:

$\bf c=3^{90}-4\cdot9^{44}+2^{208}:\big(2\cdot4^{103}\big)-5\cdot\big(9^{22}\big)^2$

$\bf c=3^{90}-2^{2} \cdot\big(3^{2}\big)^{44}+2^{208}:\Big[2\cdot\big(2^{2}\big)^{103}\Big]-5\cdot 9^{22\cdot2}$

$\bf c=3^{90}-2^{2} \cdot 3^{2\cdot44}+2^{208}:\Big(2\cdot2^{2\cdot103}\Big)-5\cdot 9^{44}$

$\bf c=3^{90}-2^{2} \cdot 3^{88}+2^{208}:\Big(2\cdot2^{206}\Big)-5\cdot \big(3^{2}\big)^{44}$

$\bf c=3^{90}-2^{2} \cdot 3^{88}+2^{208}:2^{206+1}-5\cdot 3^{2\cdot44}$

$\bf c=3^{90}-4\cdot 3^{88}+2^{208}:2^{207}-5\cdot 3^{88}$

$\bf c=3^{90}-4\cdot 3^{88}+2^{208-207}-5\cdot 3^{88}$

$\bf c=3^{90}-4\cdot 3^{88}+2^{1}-5\cdot 3^{88}$

$\bf c=3^{90}-9\cdot 3^{88}+2$.

$\bf c=3^{90}-3^{2}\cdot 3^{88}+2$

$\bf c=3^{90}-3^{2+88}+2$

$\bf c=3^{90}-3^{90}+2$

$\pink{\underline{~\bf c=2~}}$

$==pav38==$