Question

[(3+a:2):11+7]x5-8=41

Answer 1

[(3 + a:2):11 + 7] × 5 - 8 = 41

{[(3×2 + a)/2]:11 + 7} × 5 - 8 = 41

{[(6 + a)/2]:11 + 7} × 5 - 8 = 41

[(6 +a)/2 × 1/11 +7] × 5 - 8 = 41

[(6 + a)/22 +7] × 5 - 8 = 41

{[(6 + a) +7×22]/22} × 5 - 8 = 41

[(6 + a + 154)/22]× 5 - 8 = 41

(160 + a )/22]× 5 - 8 = 41
 
(5×160 + 5×a)/22 = 41 + 8

(5×160 + 5×a)/22 = 49

(5×160 + 5×a)=49 ×22

5a =49 ×22 - 5×160

5a = 1078 - 800

5a = 278

a = 55.6