Question

3.calculati:⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀​

Answer 1

Răspuns:

$a)\:\sqrt{27} +\sqrt{12}-\sqrt{75}=3\sqrt{3}+2\sqrt{3}-5\sqrt{3}=5\sqrt{x3}-5\sqrt{3}=0$

$b)\:2\sqrt{8}+3 \sqrt{18}-13\sqrt{2}=4\sqrt{2}+9\sqrt{2}-13\sqrt{2} =13\sqrt{2}-13\sqrt{2}=0$

$c)\: \sqrt{2} (\sqrt{2}+\sqrt{3} )-\sqrt{3}(2\sqrt{3}+\sqrt{2} )=2+\sqrt{6}-6-\sqrt{6}=2-6=-4$

$d)\:(\sqrt{2}-\sqrt{12})(\sqrt{8} +\sqrt{3} ) =(\sqrt{2}- 2\sqrt{3} )(2\sqrt{2} +\sqrt{3} )=4+\sqrt{6} -4\sqrt{6}-6=-2-3\sqrt{6}$