Question

3. Calculați: a) 5√5 +7√5-9√5; -5√2 + √2 + 3√2; 7√3 - 4√3-3√3; b) 6√3+ 9√7- (3√7 - 4√7); 2√11 (-2√3)-(-3√3);​

Answer 1

Răspuns:5$\sqrt{5}$ +7$\sqrt{7}$-9$\sqrt{5}$= 12$\sqrt{5}$-9    $\sqrt{5}$=3$\sqrt{5}$

-5$\sqrt{5} + \sqrt{2} + 3\sqrt{2} =-4\sqrt{2}+3\sqrt{2}=-\sqrt{2} =-1$

$7\sqrt{3} -4\sqrt{3} -3\sqrt{3} =3\sqrt{3} -3\sqrt{3} =0$

$6\sqrt{3} +9\sqrt{7} -(3\sqrt{7} -4\sqrt{7} )=6\sqrt{3}+9\sqrt{7}-(-\sqrt{7} )=6\sqrt{3}+10\sqrt{7}$

$2\sqrt{11} (-2\sqrt{3} )-(-3\sqrt{3} )=-4\sqrt{33} +3\sqrt{3} =-4\sqrt{33} +3$

Explicație pas cu pas: