Question

3. Calculaţi n2017, unde n = {3¹3: [(3. 220-220)2: 16¹0-201¹¹ + 3°}: 10.
Ajutați-mă dau coroana

Answer 1

Răspuns:

sall

Explicație pas cu pas:

n=3¹3:[(660-220)×2:16¹0-201¹¹+3⁰]:10

n=3¹3:(440×2:16¹0-201¹¹+3⁰):10

n=3¹3:(440×2:16×0-2,16349867E+25+1):10

n=3×3:(880:0-2,16349867E+25+1):10

n=9:(0-2,16349867E+25+1):10

n=9:−2,16349867E+25:10

n=−2,16349867E+24:10

n=−2,16349867E+23