Question

3. Calculează, respectând ordinea efectuării operaţiilor.
a) 515+515:5-515x0=
b) (286 − 7 × 7): 3 + (12 × 8:2 +4:4)=
c) 1 098 +700: 100-(890:10+18) x 0 =
d) 119 x (917:7) +5 234-209=
e) [675+234×4-(876:4+7434:9)]×1000=
f) 5×[(0:85+85:85)+994:7-142]+85×11=
g) 9+10×[365+10×(60+60:5)]:5=
​

Answer 1

Răspuns:

a) 515+515:5-515x0=

=515+103-0=

=618-0=

=618

b) (286-7×7):3+(12×8:2+4:4)=

=(286-49):3+(98:2+1)=

=237:3+(49+1)=

=79+50=

=128

c) 1098+700:100-(890:10+18)x0=

=1098+7-0=

=1105-0=

=1105