Question

3 Efectuați: a 3⁵¹: 3⁴⁸ +23¹×3³ +1220⁰; c 13-3 ×[7-2×(5-3)]; b 3⁴×7²+22¹ × 10³ - 154¹; d 12×{110-10×[9×8-9×(15-8] }.​

Answer 1

a) =3³+23·3³+1=3³(1+23)+1=3³×24+1=27×24+1=649

b) =81×49+22×1000-154=3969+22000-154=25969-154=25815

c) =13-3×(7-2×2)=13-3×(7-4)=13-3×3=13-9=4

d) =12×[110-10×(72-9×7)]=12×[110-10×(72-63)]=12×(110-10×9)=12×(110-90)=12×20=240

Answer 2

Răspuns:

$\bf a)~ 3^{51} : 3^{48} +23^{1}\cdot 3^{3} +1220^{0}=$

$\bf~ 3^{51-48} +23\cdot 27 +1=$

$\bf~ 3^{3} +621 +1=$

$\bf~ 27 +621 +1=\red{\underline{~649~}}$

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$\bf b)~~ 3^{4}\cdot7^{2}+22^{1}\cdot 10^{3} - 154^{1}$

$\bf ~ 3^{4}\cdot7^{2}+22\cdot 1000 - 154=$

$\bf ~ 81\cdot49+22000 - 154=$

$\bf ~3969+22000-154=$

$\bf ~25969-154=\purple{\underline{~25815~}}$

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c) 13 - 3 × [7 - 2 × (5 - 3)] =

13 - 3 × (7 - 2 × 2) =

13 - 3 × (7 - 4) =

13 - 3 × 3 = 13 - 9 = 4

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d) 12 × {110 - 10 × [9 × 8 - 9 × (15 - 8)]} =

12 × [110 - 10 × (9 × 8 - 9 × 7)] =

12 × [110 - 10 × (72 - 63)] =

12 × (110 - 10 × 9) =

12 × (110 - 90) =

12 × 20 = 240

==pav38==