Question

(3 intregi si 2/6+1 intreg si 5/7)* 1 intreg si 2/3
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1 intreg si 2/9-1 intreg si 1/18
Daca puteti sa imi si explicati! Multumesc!

Answer 1

introducem intregii in fractie
3$\frac{2}{6}$ = $\frac{3*6+2}{6}$ = $\frac{20}{6}$
1$\frac{5}{7}$ = $\frac{1*7+5}{7}$ = $\frac{12}{7}$
1$\frac{2}{3}$ = $\frac{1*2+3}{3}$ = $\frac{5}{3}$
($\frac{20}{6}$+$\frac{12}{7}$)*$\frac{5}{3}$ = 
$\frac{140+72}{42}$ * $\frac{5}{3}$ = $\frac{212}{42}$ * $\frac{5}{3}$ = $\frac{1060}{126}$ = $\frac{530}{63}$

1$\frac{2}{9}$ - 1$\frac{1}{18}$ = $\frac{11}{9}$ - $\frac{19}{18}$ = $\frac{22}{18}$ - $\frac{19}{18}$ = $\frac{3}{18}$ = $\frac{1}{6}$