Question

3 la a doua ori {2 la a treia+5 la a doua ori paranteza dreapta 4 la a saisprezecea:la 4 la a paisprezecea+1 la 2015 (15 la a doua minus 223)paranteza dreapta }

Answer 1

[tex]3^2\{2^3+5^2[4^{14}:4^{14}+1^{2015}(15^2-223)]\}=\\ 9\{8+25[1+1(225-223)]\}=\\ 9[8+25(1+2)]=\\ 9[8+25*3]=\\ 9(8+75)=\\ 9*83=747[/tex]