Question

3 la puterea 21 comparat cu 6 la puterea 14

Answer 1

$\it 3<4\Rightarrow 3<2^2\Rightarrow 3^7<(2^2)^7 \Rightarrow 3^7<2^{14}\Rightarrow|_{\cdot3^{14}}\Rightarrow3^7\cdot3^{14}<2^{14}\cdot3^{14}\Rightarrow\\ \\ \Rightarrow3^{7+14}<(2\cdot3)^{14}\Rightarrow3^{21}<6^{14}$

Sau:

$\it 3^{21}=(3^3)^7=27^7<36^7=(6^2)^7=6^{14}$