Question

3 la puterea 45 :3 la puterea 43+ (8 la puterea 15+4 la puterea 20-2 la puterea 78 : 2 la puterea75x3)totul la puterea 20 :4 la puterea 30

Answer 1

[3^45 : 3^43 +(8^15 + 4^20 - 2^78 : 2^75 x 3)]^20 : 4^30 =
{3^2 + [(2^3)^15 + (2^2)^20 - 2^78 : 2^75 x 3]}^20 : (2^2)^30 = 
[3^2 + (2^30 + 2^40 - 2^78 : 2^75 x 3]^20 : 2^60 =
(3^2 + 2^30 + 2^40 - 2^3 x 3)^20 : 2^60 =
(3^2 + 2^70 - 2^3 x 3)^20 ; 2^60 =
(3^2 + 2^67 x 3)^20 : 2^60 =
(3^2 x 3)^20 + (2^67)^20 : 2^60 =
(3^3)^20 + (2^7)20 =
(3^3 +2^7)^20 =
(9 + 128)^20 = 137^20 unde ^ inseamna "la puterea"