Question

(3 la puterea 52- 3 la puterea 51 -3 la puterea 50)totul la puterea a 2 : (9 la puterea 50× 25)

Answer 1

(3^52- 3^51 -3^50)^2 : (9^50× 25) =
=[3^50(3^2- 3^1 -3^0)]^2 : (3^100× 5^2) =
=[3^50(9-3 -1)]^2 : (3^100× 5^2) =
=(3^50 ×5)^2 : (3^100× 5^2) =
=(3^100 ×5^2) : (3^100× 5^2) =1