Question

3 radical din 8 - 4 radical din 3 - 6 radical din 8​

Answer 1

$3\sqrt{8}-4\sqrt{3}-6\sqrt{8}=-3\sqrt{8}-4\sqrt{3}=-3*2\sqrt{2}-4\sqrt{3}=-6\sqrt{2}-4\sqrt{3}=-2*(3\sqrt{2}+2\sqrt{3}).$