Question

3) scoate intregi : 7213 supra 102 , 3459 supra 93 ,12023 supra 12 Urgent !!!!

Answer 1

$\frac{7213}{102}= 70 \frac{73}{102}$
reintroduci intregii in fractie pentru verificare: $(70\cdot102+73)/102= \frac{7213}{102}$

$\frac{3459}{93}=37 \frac{18}{93}$
reintroduci intregii in fractie pentru verificare $(37\cdot93+18)/93=\frac{3459}{93}$

$\frac{12023}{12}=1001\frac{11}{12}$
reintroduci intregii in fractie pentru verificare  $(1001\cdot12+11)/12=\frac{12023}{12}$