Question

3 si 4 va rooog dau coroana​

Answer 1

Explicație pas cu pas:

A=|2+x|+|x+3|+|1-2x|-V(1+4x+4x²)=>

A=|2+x|+|x+3|+|1-2x|-V(2x+1)²=>

A=|2+x|+|x+3|+|1-2x|-|2x+1|

x=1=>A=3+4+|-1|-1=>A=7+1-1=>A=7

x(-3,-2)=>-3<x<-2=>

x+2<0

x+3>0

4<-2x<6 => 0<1-2x

-6<2x<-4=>2x+1<0

=> A= -(x+2)+x+3+1-2x-(-2x-1)=>

A= -x-2+x+3+1-2x+2x+1=>A=3 => A>=2 (A)

|0,4-1|+|0,4+2|=1-0,4+0,4+2=3

-2<=x<=1 => x-1<=0 si x+2>=0 => |x-1|+|x+2|=1-x+2+x=3

x€[-2,1] => -2<=x<=1 => x-1<=0 si x+2>=0

|x|/(|x-1|+|x+2|)=4/9 => |x|/(1-x+2+x)=4/9=>|x|/3=4/9 =>

|x|=4/3 => x=4/3 sau x=-4/3 dar cum x€[-2,1] => x=-4/3 solutie

Answer 2

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