Question

3.Stiind ca:
I.a=(6+3:3-5):2
a=
b=5-4:(8-6:1)
b=
c=(7+9):4-3×(8-2×4)
c=
Calculeaza 5×a-b:3+c:2.
II.a=(5+5:5+2:2)×2
a=
b=16:(25:5-12:3)
b=
c=2-27:(5×5+2:1)
c=
Calculeaza 2 a+38+c.​

Answer 1

A=(6+1-5):2
A=(7-5):2
A=2:2
A=1
B=5-4:(8-6:1)
B=5-4:(8-6)
B=5-4:2
B=5-2
B=3
C=2-27:(5x5+2:1)
C=2-27:(25+2)
C=2-27:27
C=2-1
C=1

2 a+38+c=
2x1+38+1=
2+38+1=
=41

Answer 2

Salutare!

Stiind că:

I.

a=(6+3:3-5):2

a=(6+1-5):2

a=(7-5):2

a=2:2

a=1

b=5-4:(8-6:1)

b=5-4:(8-6)

b=5-4:2

b=5-2

b=3

c=(7+9):4-3×(8-2×4)

c=16:4-3×(8-8)

c=4-3×0

c=4-0

c=4

Calculează:

5×a-b:3+c:2=?

5×1-3:3+4:2=5-1+2=4+2=6

II.

a=(5+5:5+2:2)×2

a=(5+1+1)×2

a=(6+1)×2

a=7×2

a=14

b=16:(25:5-12:3)

b=16:(5-4)

b=16:1

b=16

c=2-27:(5×5+2:1)

c=2-27:(25+2)

c=2-27:27

c=2-1

c=1

Calculează:

a+38+c=?

14+38+1=52+1=53