Question

3 supra 2 TREBUIE SA ARATAM INEGALITATEA
Capiron logaritmi

Answer 1

Plecam de la inegalitatea evidenta: $\sqrt[]{8}\ \textless \ 3\ \textless \ 8,o,logaritmam,in,baza,2: log_{2} \sqrt{8}\ \textless \ log_{2}3\ \textless \ log_{2}8,sau,$$log_{2} 2^{ \frac{3}{2} }\ \textless \ log_{2}3\ \textless \ log_{2}2^3,deci \frac{3}{2}\ \textless \ log_{2}3\ \textless \ 3$. se tine cont cafunctia  logaritmica in baza supraunitara este strict crescatoare.