Question

3 supra 3 radical 2 +2 radical 3​

Answer 1

$\frac{3}{3 \sqrt{2} + 2 \sqrt{3} }$

$\frac{3}{3 \sqrt{2} + 2 \sqrt{3} } \times \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} }$

$\frac{3(3 \sqrt{2} - 2 \sqrt{3} )}{(3 \sqrt{2 } + 2 \sqrt{3} ) + (3 \sqrt{2} - 2 \sqrt{3} )}$

$\frac{3(3 \sqrt{2} - 2 \sqrt{3}) }{9 \times 2 - 4 \times 3}$

$\frac{3(3 \sqrt{2} - 2 \sqrt{ 3} )}{18 - 12}$

$\frac{3(3 \sqrt{2} - 2 \sqrt{3}) }{6}$

Simplifici 3 cu 6,prin 3 si iti iese:

$\frac{3 \sqrt{2} - 2 \sqrt{3} }{2}$

Sper ca ai inteles ce am facut :)