Question

3 supra 7+ 4 supra 5 +1 supra 35=
14 supra 3+ 1 supra 6+ 1 supra 2=
15 supra 9-7 supra 2+ 1 supra 3=
45 supra 9:6 supra 18=
4 intregi si 1 supra 9: 3 supra 27=
0,(3)+1,(4)=

Answer 1

* inmultit

3/7+ 4/5 +1/35=(3*5+4*7+1)/35=(15+28+1)/35=44/35

14/3+ 1/6+ 1/2=(14*2+1+1*3)/6=(28+1+3)/6=32/6=16/3

15/9-7/2+ 1/3=5/3-7/2+ 1/3=6/3-7/2=2-7/2=(4-7) /2=-3/2

45/9:6/18=5 :1/3= 5×3=15

4 intregi si 1/9: 3/27=37/9 :1/9=37/9×9=37

0,(3)+1,(4)= 3/9+(14-1)/9=3/9+13/9=16/9