Question

3 x^{2} -12x >0 Va rog rezolvarea !!

Answer 1

3x^2-12x>0
x(3x-12)>0
x>0 sau 3x-12>0=>3x>12=>x>12/3=>x>4
x<0 x apartine (-∞,0) sau x>4 x apartine (4,∞)
3x^2-12x>0 |:3
x^2-4x>0
x^2-4x=0 
delta=b^2-4ac=16
x1=4+4/2=4
x2=4-4/2=0
S={0,4}