Question

3-x^2 /16 = 1/8

3x/2=2/3x​

Answer 1

$\frac{3-x^2}{16} =\frac{1}{8} \\8(3-x^2)=16\\24-8x^2=16\\-8x^2=16-24\\-8x^2=-8 |*(-1)\\8x^2=8\\x=\sqrt{\frac{8}{8} } =\sqrt{1} =1\\x_2=-\sqrt{1} =-1$

$\frac{3x}{2} =\frac{2}{3x} \\(3x)^2=2^2\\3^2x^2=4\\9x^2=4\\x^2=\frac{4}{9} \\x=\sqrt{\frac{4}{9} } =\frac{2}{3} \\x_2=-\sqrt{\frac{4}{9} } =-\frac{2}{3}$

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Answer 2

Răspuns:

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Explicație pas cu pas:

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