Question

3(x-2)>2(x+1) va rog ... cine mă poate ajuta

Answer 1

$3(x - 2) > 2(x + 1)$

$3x - 6 > 2x + 2$

$3x - 2x > 2 + 6$

$x > 8$

$x \: \in \: (8, + \infty )$

Answer 2

$\it 3(x - 2) > 2(x + 1) = = > \\ \it 3x - 6 > 2x + 2 = = > \\ \it 3x - 2x > 2 + 6 = = > \\ \it \mathbf{x > 8} \\ \it \mathbf S = \{ \: 9, 10, 11, ..... \}$