Question

(3-x)(x+3)=(x+2)supra 2-(x+1)(x-5)

Answer 1

[tex](3-x)(x+3)=\dfrac{x+2}{2}-(x+1)(x-5)\\ 9-x^2=\dfrac{x+2}{2}-x^2-x+5x+5\\ 4-4x=\dfrac{x+2}{2}|\cdot 2\\ 8-8x=x+2\\ 9x=6\\ x=\dfrac{6}{9}=\dfrac{2}{3}\\ S=\dfrac{2}{3}[/tex]