Question

30 de g de puritate 90 la suta reactioneza cu apa formand apa de var . Ce masa de hidroxid se calciu se formeza?Va rog!!!!!!!​

Answer 1

Răspuns:

100g CaO........90g pur

30g CaO.........xg pur

x=30×90/100=27g

MCaO=40+16=56g/mol

MCa(OH)2=40+2×16+2×1=74g/mol

56g...........................74g

CaO + H2O => Ca(OH)2

27g.........................yg

y=27×74/56=calculează