Question

31. Dacă x + y = 8 şi y + 22-35,
a) 5x + 13y + 162; b) 3y - 2x + 10z;
c) 7x+10y+6z= ;d) 4•(2z+y)+3x+3y
DAU COROANAAAA !!!!

Answer 1

Răspuns:

Dacă x + y = 8 şi y + 2z = 35

$\bf a)~5x + 13y + 16z = 5x+5y+8y+16z=$

$\bf 5\cdot(x+y)+8\cdot(y+2z)=5\cdot8+8\cdot35=$

$\bf =40+280=\blue{\underline{~320~}}$

___________________________

$\bf b)~ 3y-2x+10z=5y+10z-2y-2x=$

$\bf 5\cdot (y+2z)-2\cdot(y+x)=5\cdot 35-2\cdot 8=$

$\bf 175-16 = \pink{\underline{~159~}}$

___________________________

$\bf c) ~~7x+10y+6z=7x+7y+3y+6z=$

$\bf 7\cdot(x+y)+3\cdot(y+2z)=7\cdot 8+3\cdot 35=$

$\bf 56+105=\purple{\underline{~161~}}$

___________________________

$\bf d)~4\cdot(2z+y)+3x+3y =4\cdot(2z+y)+3\cdot(x+y)=$

$\bf 4\cdot 35+3\cdot8=140+24=\red{\underline{~164~}}$

$==pav38==$

Answer 2

Răspuns:

Explicație pas cu pas: