Question

32^19:2^19 Arătați ca sunt pătrate perfecte
81^125​

Answer 1

Răspuns:

${32}^{19} \div {2}^{19} = {16}^{19} =( {4}^{2} ) ^{19} = ( {4}^{19} ) ^{2} = p.p. \\ {81}^{125} = ({9}^{2} ) ^{125} = ({9}^{125} ) ^{2}$