Question

32-3x[15-2x(16-36:a)]-10=1 a=?​

Answer 1

Răspuns:

32-3x[15-2x(16-36/*supra*a)]-10=1 ; a diferit de 0

32-3x(15-32+72/*supra*a)-10=1

32-3x(-17+72/*supra*a)-10=1

32+51 -216/*supra*a -10=1

73-216/*supra*a=1

-216/*supra*a=1-73

-216/*supra*a= -72 | x(-1)

216 = 72a

a = 3 ; a diferit de 0