Question

320÷((340-(120-4*x))÷10+6)=10 ajutatima va rog frumos dau coroana rapid

Answer 1

$\\\frac{320}{\left(\frac{\left(340-\left(120-4x\right)\right)}{10}+6\right)}=10$

Inmultim in ambele parti cu $\frac{340-\left(120-4x\right)}{10}+6$

$\frac{320}{\frac{340-\left(120-4x\right)}{10}+6}\left(\frac{340-\left(120-4x\right)}{10}+6\right)=10\left(\frac{340-\left(120-4x\right)}{10}+6\right)$

Simplifici $320=10\left(\frac{340-\left(120-4x\right)}{10}+6\right)$

Imparti la 10 in ambele parti $\frac{10\left(\frac{340-\left(120-4x\right)}{10}+6\right)}{10}=\frac{320}{10}$

Simplifici iar $\frac{2\left(x+55\right)}{5}+6=32$

Scazi 6 in ambele parti $\frac{2\left(x+55\right)}{5}+6-6=32-6$

Amplifici cu 5 $\frac{5\cdot \:2\left(x+55\right)}{5}=26\cdot \:5$

$2\left(x+55\right)=130$

Imparti cu 2 $\frac{2\left(x+55\right)}{2}=\frac{130}{2}$

$x+55=65$

Scazi 55 din ambele parti $x+55-55=65-55$

Simplifici si ramane $x=10$