Question

(325-325)·[256+1435/(48+239)]=
[500-(3500/700·80-40·9)·(64/8)]/9-(72/6)/(81/27)=
[450/5/(3·6)+35]·7-140+(540/60+7)·(63/9)=
2·{350/[491-3·(125-78)]+350}=
dau coronita e urgent va rog dati cu calcul de supt acar 2

Answer 1

$(325-325)*[256+1435:(48+239)]= \\ 0 *(256 + 1435:287)= \\ 0*(256+5)= \\ 0*261=0$

$[500-(3500:700*80-40*9)*(64:8)]:9-(72:6):(81:27)= \\500-(5*80-360)*8]:9-(12:3)= \\ 500-(400-360)*8]:9-4= \\ 500-40*8]:9-4= \\ 180:9-4=20-4=16$

$[450:5:(3*6)+35]*7-140+(540:60+7)*(63:9)= \\ (450:5:18+35)*7-140+(9+7)*7= \\ (90:18+35)*7-140+16*7= \\ (5+35)*7-140+112= \\ 40*7-140+112= \\ 280-140+112= \\ 140+112=252$


$2*{350:[491-3*(125-78)]+350}= \\ 2*{350:[491-3*47]+350}= \\ 2*{350:[491-141]+350}= \\ 2*{350:350+350}= \\ 2*{1+350}=2*351=702$