Question

[328×1+(7+7×27-9×21+195÷3)]:100

Answer 1

[tex][328*1+(7+7*27-9*21+195:3)]:100 =\ \textgreater \ [/tex]
$[328*1+(7+189-189+65)]:100 =\ \textgreater$
$[328*1+(7+0+65)]:100 =\ \textgreater$
$(328*1+72):100 =\ \textgreater$
$(328+72):100 =\ \textgreater$
$400:100 =\ \textgreater$
$\frac{400}{100} =\ \textgreater$
$=\ \textgreater \ 4\ \textless \ =$