Question

[333÷3+(77×7-39+258)-98]×3=​

Answer 1

Răspuns:

[333÷3+(539-39+258)-98]×3

=[333÷3+(500+258)-98]×3

=(333÷3+758-98)×3

=(111+758-98)×3

=(869-98)×3

=771×3

=2313

Answer 2

Explicație pas cu pas:

☆Bună!☆

[333:3+(77×7-39+258)-98]×3=

[111+(77×7-39+258)-98]×3=

[111+(539-39+258)-98]×3=

[111+(500+258)-98]×3=

(111+758-98)×3=

(869-98)×3=

771×3=

2 313