Question

350 g solutie de acid sulfuric cu concentratie de cantitate de clorura de barium stiind ca randamentul reactiei este de 90 la suta , calculati masa de clorura de bariu de puritate 75 la suta
DAU COROANA !!!!

Answer 1

ms = 350g , c% = 70%

stim ca c% = mdx100/ms

=> md = msxc%/100 = 350x70/100 = 245g H2SO4

M.H2SO4 = 2x1+32+4x16 = 98 g/mol

M.BaCl2 = 137+2x35,5 = 208 g/mol

245g        m g

H2SO4 + BaCl2 --> BaSO4 + 2HCl

98            208

=> m = 245x208/98 = 520 g BaCl2 pur consumat teoretic la 100% ... dar noi aven randament de 90% deci practic cat s-a consumat

100% .......................... 520g BaCl2 (Ct)

90% ............................ Cp = 468 g BaCl2 pur consumat practic

75% ...................... 568g BaCl2 pur (m.pura)

100% ..................... m.impura = 624 g BaCl2