Question

35supta 88× 11supta5-(-1supra 2 )la puterea a3+5÷(5-2supta51×102supra 5)

Answer 1

$\frac{35}{88} * \frac{11}{5} -(- \frac{1}{2} ) ^{3} +5:(5- \frac{2}{51} * \frac{102}{5} )= \frac{7}{8} + \frac{1}{8} +5:(5- \frac{4}{5} )$
$\frac{8}{8} +5: \frac{25-4}{5} =1+5* \frac{5}{21} =1+ \frac{25}{21} = \frac{21+25}{21} = \frac{46}{21}$