Question

366÷{24^5÷2^15÷3^4+9^17÷(3^2)^16×[10^2÷5-(32^6×2^8-4^19)×5]}

Answer 1

Răspuns:

2

Explicație pas cu pas:

366:{24^5:2^15:3^4+9^17:(3^2)^16×[10^2:5-(32^6×2^8-4^19)×5]} =

= 366:{(2^15×3^5):2^15:3^4+9^17:9^16×[100:5-(2^30×2^8-2^38)×5]} =

= 366 : {3 + 9 × [20 -(2^38 - 2^38) × 5]} =

= 366 : [3 + 9 × (20 - 0)] =

= 366 : ( 3 + 9 × 20) =

= 366 : (3 + 180) =

= 366 : 183 =

= 2

( 24^5 = 2^5×3^5×4^5 = 3^5×2^5×2^10 = 3^5×2^15)