Question

37,1 va rog frumos ​

Answer 1

Răspuns:

37.A.(x-1)/(2×+3)

(×-1)/(×-1) /2

---------------

(×-1)/(2×+3)

(x-1)/(2×-1)

---------------(-)

(x+1)/3-(-1)

(x+1)/4

=>(×+1)=D4

x+1={1,2,4} /-1

A={0,1,3}

B. (2×+3)/(3×+7) /×2

(2x+3)/(2×+3) /×3

----------------

(2×+3)/(6×+21)

(2×+3)/(6×+9)

----------------(-)

(2x+3)/21-9

(2×+3)/12

=>(2×+3)=D12

(2x+3)={1,2,3,4,6,12} /-3

2×= {0,1,3,9} /:2

B={0} -restul nu pot fi ca iti cere nr in N

1.A. ×/12

×=D12

×={1,2,3,4,6,12}

B. 2/×

×=M2

×={2,4,6,8,10,12,14,16,..}

C. ×/15

x=D15

x={1,3,5,15}

D. 3/x

x=M3

x={3,6,9,12,15,18,21,...}