Question

398,87 g Na Cl reactioneaza cu o solutie de H2So4
12% impuritati
a) mH2SO4 ?
b) masa sare ?
c) m HCl ?

Answer 1

%pur=100-12=88

p=mp/mimp*100=>mp=p*mimp/100=88*398,87/100=351g NaCl

MNaCl=ANa+ACl=23+35,5=58,5g/mol

n=m/M=351/58,5=6 moli NaCl

2NaCl + H2SO4 => Na2SO4 + 2HCl

a) 2 moli NaCl.....................98g H2SO4
6 moli NaCl..........................xg H2SO4

x=98*6/2 = Calculeaza !!

MH2SO4=2AH+AS+4AO=2*1+32+4*16=98g/mol

b) 2 moli NaCl......................142g Na2SO4 (sare)
6 moli NaCl.............................xg Na2SO4

x=142*6/2 = Calculeaza !!

MNa2SO4=2ANa+AS+4AO=2*23+32+4*16=142g/mol

c) 2 moli NaCl.................................2*36,5g HCl
6 moli NaCl...........................................xg HCl

x=73*6/2 = Calculeaza !!

MHCl=AH+ACl=1+35,5=36,5g/mol

SUCCES !