Question

(3a-4ax+2)-(11a-4ax)=
(2a-1)(3a+4)=
(y-4)^2=
(7x+a)^2=
(3a+2b)(3a-2b)=
(2a+5)^3=
(4a-3b)^3=
(x^3-1)=
8x^3+125=
Urgent dau coroana

Answer 1

(3a-4ax+2)-(11a-4ax)=3a-4ax+2-11a+4ax=-8a+2
(2a-1)(3a+4)=2a(3a+4)-1(3a+1)=6a^2+8a-3a-1=6a^2+5a-1
(y-4)^2=y^2-2×y×4+4^2=y^2-8y+16
(7x+a)^2=(7x)^2+2×7x×a+a^2=49x^2+14ax+a^2
(3a+2b)(3a-2b)=(3a)^2-(2b)^2=9a^2-4b^2

Answer 2

(3a-4ax+2)-(11a-4ax)=-8a+2  
(2a-1)(3a+4)=6a²+8a-3a-4=6a²+5a-4  
(y-4)²=y²-2·y·4+4²=y²-8y+16 
(7x+a)²=(7x)²+2·7x·a+a²=49x²+14ax+a²  
(3a+2b)(3a-2b)=(3a)²-(2b)²=9a²-4b²  
(2a+5)³=(2a)³+3·(2a)²·5+3·(2a)·5²+5³=8a³+60a²+150a+125  
(4a-3b)³=(4a)³-3·(4a)²·(3b)+3·(4a)·(3b)²-(3b)³=64a³-144a²b+108ab²-27b³  
(x³-1³)=(x-1)(x²+x+1)  
8x³+125=(2x)³+5³=(2x+5)[(2x)²-2x·5+5²]=(2x+5)(4x²-10x+25)