Question

3a si 4a va rog mult! este urgent! :((

Answer 1

(x+2)(y-3)=(x-3)(y+2)+30
x(2x-y+1)=2x²-x(y-2)-13

xy+2y-3x-6=xy-3y+2y-6+30
2x²-xy+x=2x²-xy+2x-13

-3x=-3y+30                               
2x²-xy+x=2x²-xy+2x-13 
y=10+x
x=13
y=10+13=23



3[4x-3(x+1)]+8=2y-x
5[2x-4(x+1)]+24=6(x-y)

3(4x-3x-2)+8=2y-x
5(2x-4x-4)+24=6x-6y

12x-9x-6+8=2y-x
10x-20x-20+24=6x-6y

4x+2=2y
-10x+4=6x-6y

2x+1=y
16x-6y=4

2x+1=y
8x-3y=2

8x-3(2x+1)=2
8x-6x-3=2
2x=5
x=5/2
y=2×5/2+1=6