Question

(3la puterea 32 : 3 la puterea 2 + 2 la puterea 2 x 2 la puterea 25 - 2019 la puterea 0) :( 27 la puterea 10 + 8 la puterea 9 - 324 : 18 la puterea 2) =
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Answer 1

Răspuns:

3^32:3^2+2^2×2^25-2019^0:(27^10+8^9-324:18^2)=(3^30+2^27-1):(27^10+8^9-1)=(3^30+2^27-1):((3^3)^10+(2^3)^9-1)=(3^30+2^27-1)÷(3^30+2^27-1)=1 se observa ca ambii termeni sunt egali, atunci ceva impartit la el insusi este=1

......BAFTA......