Question

3radical 0+3+3radical2+3radical3+3radical4

Answer 1

$3 \sqrt{0} + 3 + 3 \sqrt{2} + 3 \sqrt{3} + 3 \sqrt{4}$

$= 3 \times 0 + 3 + 3 \sqrt{2} + 3 \sqrt{3} + 3 \times 2$

$= 0 + 3 + 3 \sqrt{2} + 3 \sqrt{3} + 6$

$= 9 + 3 \sqrt{2} + 3 \sqrt{3}$

$= 3(3 + \sqrt{2} + \sqrt{3} )$