Question

3radical din 242×(radical din 288-2 radical din 50-radical din 32)

Answer 1

3√242 × ( √288 - 2√50 - √32 ) = - 132

= 3 × 11√2 × ( 12√2 - 2× 5√2 - 4√2 ) =

= 33√2 × ( 12√2 - 10√2 - 4√2 ) =

= ( 33√2 × 12√2 ) - ( 33√2 × 10√2 ) - ( 33√2 × 4√2 ) =

= ( 396 ×√4 ) - ( 330 × 2 ) - ( 132 × 2 ) =

= 792 - 660 - 264 =

= 132 - 264 =

= - 132

Answer 2

$3 \sqrt{242} \times ( \sqrt{288} - 2 \sqrt{50} - \sqrt{32}) = \\ \\ 3 \times 11 \sqrt{2}(12 \sqrt{2} - 2 \times 5 \sqrt{2} - 4 \sqrt{2}) = \\ \\ 3 \times 11 \sqrt{2}(12 \sqrt{2} - 10 \sqrt{2} - 4 \sqrt{2}) = \\ \\ 3 \times 11 \sqrt{2} \times - 2 \sqrt{2} = \\ \\ - 3 \times 11 \times 2 \sqrt{2 \times 2} = \\ \\ - 3 \times 11 \times 2 \sqrt{4} = \\ \\ - 3 \times 11 \times 2 \times 2 = \\ \\ - 33 \times 4 = \\ \\ - 132$