Question

3radical48-5radical3-2radical27​

Answer 1

$\it 3\sqrt{48} - 5\sqrt{3} - 2\sqrt{27} = 3 \cdot 4\sqrt{3} - 5\sqrt{3} - 2 \cdot 3\sqrt{3} = 12\sqrt{3}  - 5\sqrt{3}  - 6\sqrt{3} = \sqrt{3}$

Answer 2

3√48 - 5√3 - 2√27 =

= 3√16·3 - 5√3 - 2√9·3

= 3√4²·3 - 5√3 - 2√3²·3

= 12√3 - 5√3 - 6√3

= 12√3 - 11√3

= √3