Question

(3x+1)totul la a doua minus 3=6

Answer 1

$(3x+1)^2-3=6 \\ (3x+1)^2-3-6=0 \\(3x-1)^2-9=0 \\ Faci~diferenta~de~patrate: \\ (3x-1-3)(3x-1+3)=0 \\ (3x-4)(3x+2)=0 \\ \\ I.3x-4=0 \rightarrow 3x=4 \rightarrow x=\frac43 \\ \\ II.3x+2=0 \rightarrow 3x=-2 \rightarrow x=-\frac23 \\ \\S=\{\frac43, -\frac23\}$

Answer 2

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