Question

(3x-1)/(x+1) + (x+1)/(2x-1)=3

Answer 1

(3x-1)/(x+1) + (x+1)/(2x-1)=3
3x/(x+1)-1/(x+1)+(x+1)/(2x-1)=3
-1/(x+1)+3x/(x+1)+1/(2x-1)+x/(2x-1)=3
3x/(x+1)-1/(x+1)+x/(2x-1)+1/(2x-1)=3
(x+1)/(2x-1)+(3x-1)/(x+1)=3
(7x²-3x+2)/[(x+1)(2x-1)]=3
7x²-3x+2=3(x+1)(2x-1)
7x²-3x+2=6x²+3x-3
x²-6x+5=0
(x-5)(x-1)=0
x-5=0=>x₁=5
x-1=0=>x₂=1

Answer 2

(3x-1)(2x-1)+(x+1)(x+1) supra (x+1)(2x-1) este 3
6x^2-2x-3x+1+x^2+2x+1 supra 2x^2-x+2x-1 este 3
7x^2-3x+2 supra 2x^2+x-1 este 3
7x^2-3x+2=6x^2+3x-3
x^2-6x+5=0
(x-1)(x-5)=0
=> x1=1, x2=5