Question

3x/2 =5y/3=2z/5 x+y+z=226
x, y, z?
Va rog!!! Dau coroana
/=semnul de fractie​

Answer 1

Răspuns:

3x/2 =5y/3=2z/5=k → coeficient de proportionalitate

x=2/3k

y=3/5k

z=5/2k

x+y+z=226

¹⁰⁾2/3k+⁶⁾3/5k+¹⁵⁾5/2k=³⁰⁾226

20k+18k+75k=6780

113k=6780=>k=6780:113=>k=60

x=(2·60)/3=40

y=(3·60)/5=36

z=(5·60)/2=150

Answer 2

$\frac{3x}{2} = \frac{5y}{3} = \frac{2z}{5} x + y + z = 226$

$x = \frac{452}{3} = 150 \frac{2}{3}$

$y = \frac{678}{5} = 135 \frac{3}{5}$

$z = \frac{1356}{919} = 1 \frac{437}{919}$

Sper ca ti-am fost de folos. Succes!!!