Question

(3x^2) x (|x-2|-1)<_0 plssssss, dau coroana​

Answer 1

$\it 3x^2(|x-2|-1)\leq0 \Rightarrow \begin{cases}\it x^2=0 \Rightarrow x=0\ \ \ \ \ (1)\\ \\ \it |x-2|-1\leq0 \Rightarrow |x-2|\leq1\ \ \ \ (2)\end{cases}\\ \\ \\ (2) \Rightarrow -1\leq x-2\leq1|_{+2} \Rightarrow 1\leq x\leq 3 \Rightarrow x\in[1,\ \ 3]\ \ \ \ \ \ \ \ (3)$

$\it (1),\ (3) \Rightarrow S=[1,\ \ 3]\cup\{0\}$

             ( mulțimea soluțiilor )