Question

3x la a 2 minus 2x minus 2 mai mare ca 0.

Answer 1

Răspuns:

Explicație pas cu pas:

$3x^{2} -2x-2 > 0$

$3x^{2} -2x-2=0\\2^{2}-4*3*(-2)=4+24=28$

$x_{1}=\frac{-(-2)-\sqrt{28} }{6}=\frac{2-2\sqrt{7} }{6}=\frac{1-\sqrt{7} }{3}\\x_{2}=\frac{-(-2)+\sqrt{28} }{6}=\frac{2+2\sqrt{7} }{6}=\frac{1+\sqrt{7} }{3}$

$x\in(-\infty,\frac{1-\sqrt{7} }{3}) U (\frac{1+\sqrt{7} }{3};+\infty)$