Question

3x²+4x-4=0 de gradul 2

Answer 1

3x²+4x-4=0
Δ = 16 - 4×3×(-4) = 16 + 48 = 64 
x₁ = (-4+8)/6 = 4/6  = 2/3
x₂ = (-4 - 8)/6 = -12/6 = -2 

S = { -2; 2/3} 

Answer 2

3x²+4x-4=0
x = -4+/-√4²-4*3*(-4)/2*3
x = -4+/-√16+48/6
x = -4+/-√64/8

x = (-4+8)/6 = ) x = 2/3
x = (-4-8)/6 =) x = -2

=) S = { -2 , 2/3}